$25.4 \mathrm{~g}$ of $\mathrm{I}_{2}$ and $14.2 \mathrm{~g}$ of $\mathrm{Cl}_{2}$ are made to react completely to yield a mixture of $\mathrm{ICl}$ and $\mathrm{ICl}_{3}$ Calculate moles of ICl and $\mathrm{ICl}_{3}$ formed

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Aicharya · Accepted Answer

$\begin{array}{lcc}
& \mathrm{I}_{2} & + & 2 \mathrm{Cl}_{2} & \longrightarrow & \mathrm{ICl} & + & \mathrm{ICl}_{3} \\
\text{No. of moles } & \frac{25.4}{254} & & \frac{14.2}{71} & & 0 & & 0 \\
\text{initially } & 0.1 & & 0.2 & & 0 & & 0 \\
\text{No. of moles } & 0 & & 0 & & 0.1 & & 0.1 \\
\end{array}$ ~

$25.4 \mathrm{~g}$ of $\mathrm{I}_{2}$ and $14.2 \mathrm{~g}$ of $\mathrm{Cl}_{2}$ are made to react…

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