$0.16 \mathrm{~g}$ of an organic compound containing sulphur produces $0.233 \mathrm{~g}$ of…
$0.16 \mathrm{~g}$ of an organic compound containing sulphur produces $0.233 \mathrm{~g}$ of $\mathrm{BaSO}_4$. Percentage of sulphur in the compound is
20
80
50
10
Solution
Percentage of S
$\begin{aligned}
& =\frac{32 \times \text { weight of } \mathrm{BaSO}_4 \times 100}{233 \times \text { weight of compound }} \\
& =\frac{32 \times 0.233 \times 100}{233 \times 0.16} \\
& =20
\end{aligned}$