$4 \mathrm{~g}$ of an ideal gas occupies $5.6035 \mathrm{~L}$ of volume at $546 \mathrm{~K}$ and 2…

$4 \mathrm{~g}$ of an ideal gas occupies $5.6035 \mathrm{~L}$ of volume at $546 \mathrm{~K}$ and 2 atmosphere pressure. What is its molecular weight?
  1. $4$
  2. $16$
  3. $32$
  4. $64$

Solution

$\begin{aligned} & W=4 \mathrm{~g}, V=5.6035 \mathrm{~L}, T=546 \mathrm{~K}, P=2 \mathrm{~atm} \\ & \\ & \qquad \frac{M}{W}=\frac{R T}{P V} \quad\left(\because n=\frac{W}{M}\right) \\ & \frac{M}{4}=\frac{0.0821 \times 546}{2 \times 5.6035} \\ & \therefore \quad M=16\end{aligned}$

Asked in: AP EAMCET 2002

Practice more States of Matter questions on Aicharya