$0.45 \mathrm{~g}$ of acid molecular weight 90 is neutralised by $20 \mathrm{ml}$ of $0.5 \mathrm{~N}$ caustic potash. The basicity of acid is

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Aicharya · Accepted Answer

Eq. of acid = Eq of base, $\begin{array}{l} 	herefore \frac{0.45}{\mathrm{E} \cdot \mathrm{wt}}=\frac{20 	imes 0.5}{1000}=\mathrm{E} \mathrm{wt}=45 \ 	ext { Basicity }=\frac{\mathrm{M} \cdot \mathrm{wt}}{\mathrm{E} \cdot \mathrm{wt}}=\frac{90}{45}=2 \end{array}$

$0.45 \mathrm{~g}$ of acid molecular weight 90 is neutralised by $20 \mathrm{ml}$ of $0.5 \mathrm{~N}$…

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