$100 \mathrm{~mL}$ of $0.2 \mathrm{M}$ acetic acid is completely neutralised using a standard solution of…
$100 \mathrm{~mL}$ of $0.2 \mathrm{M}$ acetic acid is completely neutralised using a standard solution of $\mathrm{NaOH}$. The volume of ethane obtained at STP after complete electrolysis of the resulting solution is
$11.2 \mathrm{~L}$
$2.24 \mathrm{~L}$
$0.224 \mathrm{~L}$
$22.4 \mathrm{~L}$
Solution
Given moles of acetic acid
$
\begin{array}{r}
=\frac{0.2 \times 100}{1000}=0.02 \text { moles } \\
2 \mathrm{CH}_3 \mathrm{COOH} \longrightarrow \mathrm{C}_2 \mathrm{H}_6+2 \mathrm{CO}_2+\mathrm{H}_2
\end{array}
$
2 moles of $\mathrm{CH}_3 \mathrm{COOH}$ gives 1 mole of ethane $=22.4 \mathrm{~L}$
0.02 moles of $\mathrm{CH}_3 \mathrm{COOH}$ will give ethane
$
=\frac{22.4 \times 0.02}{2}=0.224 \mathrm{~L}
$
$\therefore 0.224 \mathrm{~L}$ of ethane is obtained