$\mathrm{pH}$ of a $0.01 \mathrm{M}$ solution $\left(K_a=6.6 \times 10^{-4}\right)$
$\mathrm{pH}$ of a $0.01 \mathrm{M}$ solution $\left(K_a=6.6 \times 10^{-4}\right)$
- $7.6$
- $8$
- $2.6$
- $5$
Solution
$\begin{aligned} & \text { } \alpha=\sqrt{\frac{K_a}{C}}=\sqrt{\frac{6.6 \times 10^{-4}}{0.01}}=\sqrt{6.6 \times 10^{-2}}=0.257 \\ & {\left[\mathrm{H}^{+}\right]=\mathrm{C} \alpha=0.01 \times 0.257=2.57 \times 10^{-3}} \\ & \mathrm{pH}=3-\log 2.5=2.60\end{aligned}$
Asked in: NEET 2016 (Phase 2)
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