$\mathrm{pH}$ of a $0.01 \mathrm{M}$ solution $\left(K_a=6.6 \times 10^{-4}\right)$

$\mathrm{pH}$ of a $0.01 \mathrm{M}$ solution $\left(K_a=6.6 \times 10^{-4}\right)$
  1. $7.6$
  2. $8$
  3. $2.6$
  4. $5$

Solution

$\begin{aligned} & \text { } \alpha=\sqrt{\frac{K_a}{C}}=\sqrt{\frac{6.6 \times 10^{-4}}{0.01}}=\sqrt{6.6 \times 10^{-2}}=0.257 \\ & {\left[\mathrm{H}^{+}\right]=\mathrm{C} \alpha=0.01 \times 0.257=2.57 \times 10^{-3}} \\ & \mathrm{pH}=3-\log 2.5=2.60\end{aligned}$

Asked in: NEET 2016 (Phase 2)

Practice more Ionic Equilibria questions on Aicharya