$12 \mathrm{~g}$ of a nonvolatile solute dissolved in $108 \mathrm{~g}$ of water produces the relative lowering of vapour pressure of $0.1$. The molecular mass of the solute is :

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Aicharya · Accepted Answer

$\frac{\mathrm{P}^{\mathrm{o}}-\mathrm{P}_s}{\mathrm{P}^{\mathrm{o}}}=\frac{n}{N}=\frac{w}{m} 	imes \frac{\mathrm{M}}{W}$ $0.1=\frac{12}{m} 	imes \frac{18}{108}$ $m=\frac{12 	imes 18}{0.1 	imes 108}=20$

$12 \mathrm{~g}$ of a nonvolatile solute dissolved in $108 \mathrm{~g}$ of water produces the relative…

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