Observe the following statements, which are incorrect? i. The dipole moment of $\mathrm{NH}_3$ is higher…

Observe the following statements, which are incorrect? i. The dipole moment of $\mathrm{NH}_3$ is higher than the dipole moment of $\mathrm{NF}_3$. ii. The dipole moment of chloroform is zero. iii. Covalent bond character in $\mathrm{NaCl}$ is more compared to $\mathrm{CuCl}$.
  1. i, iii
  2. ii, iii
  3. i, ii, iii
  4. i, ii

Solution

Statement i. The dipole moment of \(\mathrm{NH}_{3}\) is higher than the dipole moment of \(\mathrm{NF}_{3}\).  This statement is correct. Both \(\mathrm{NH}_{3}\) and \(\mathrm{NF}_{3}\) have a trigonal pyramidal geometry with a lone pair of electrons on the nitrogen atom. In \(\mathrm{NH}_{3}\), nitrogen is more electronegative than hydrogen, so the bond dipoles point from H to N. The dipole moment due to the lone pair on nitrogen points in the same direction as the resultant of the N-H bond dipoles, making them additive and resulting in a high net dipole moment (around 1.47 D).In \(\mathrm{NF}_{3}\), fluorine is more electronegative than nitrogen, so the bond dipoles point from N to F (away from the N atom). The dipole moment due to the lone pair on nitrogen points in the opposite direction to the resultant of the N-F bond dipoles, making them subtractive and resulting in a very low net dipole moment (around 0.24 D).  . Statement ii. The dipole moment of chloroform is zero.  This statement is incorrect. Chloroform (\(\mathrm{CHCl}_{3}\)) has a tetrahedral geometry, but it is not a perfectly symmetrical molecule like carbon tetrachloride (\(\mathrm{CCl}_{4}\)) or methane (\(\mathrm{CH}_{4}\)). The bond dipoles of the three C-Cl bonds and one C-H bond do not cancel each other out due to the difference in electronegativity and the resulting asymmetrical arrangement of charges. It has a net dipole moment of approximately 1.15 D.  . Statement iii. Covalent bond character in \(\mathrm{NaCl}\) is more compared to \(\mathrm{CuCl}\). This statement is incorrect. According to Fajan's rules, \(\mathrm{CuCl}\) has a more covalent character than \(\mathrm{NaCl}\). This is because the \(\mathrm{Cu}^{\mathrm{+}}\) ion has a greater polarizing power than the \(\mathrm{Na}^{\mathrm{+}}\) ion. \(\mathrm{Cu}^{\mathrm{+}}\) has a pseudo-inert gas electron configuration (\(3d^{10}\)) while \(\mathrm{Na}^{\mathrm{+}}\) has a noble gas configuration (\(2p^{6}\)). The greater polarizing power of \(\mathrm{Cu}^{\mathrm{+}}\) causes a larger distortion of the electron cloud of the \(\mathrm{Cl}^{\mathrm{-}}\) anion, leading to increased covalent character in \(\mathrm{CuCl}\).  . In summary: Statement i is correct.Statement ii is incorrect.Statement iii is incorrect.

Asked in: AP EAMCET 2018 (24 Apr Shift 2)

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