Number of zeros at the end of $(60)^{2}$ is

Number of zeros at the end of $(60)^{2}$ is
  1. $1$
  2. $2$
  3. $0$
  4. $3$

Solution

$60^{2} = 3600$. It has 2 trailing zeros (the square doubles the count of trailing zeros).

Asked in: IMO

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