Number of trailing zeros in $5^{10} \cdot 2^{12}$ is

Question

Aicharya · Accepted Answer

Pair $5$s with $2$s to make $10$s. Min$(10, 12) = 10$ pairs $\Rightarrow 10^{10} \cdot 2^{2} = 4 	imes 10^{10}$, which has 10 trailing zeros.

Solution