Number of trailing zeros in $2^{15} \cdot 5^{12}$ is

Number of trailing zeros in $2^{15} \cdot 5^{12}$ is
  1. $12$
  2. $15$
  3. $27$
  4. $3$

Solution

Trailing zeros = min(power of 2, power of 5) = min$(15, 12) = 12$.

Asked in: IMO

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