Number of molecules having bond order 2 from the following molecules is ________ \(\mathrm{C}_2,…

Number of molecules having bond order 2 from the following molecules is ________ \(\mathrm{C}_2, \mathrm{O}_2, \mathrm{Be}_2, \mathrm{Li}_2, \mathrm{Ne}_2, \mathrm{~N}_2, \mathrm{He}_2\)

Solution

$\begin{aligned} & \mathrm{C}_2 \\ & \left(12 \mathrm{e}^{-}\right): \sigma 1 \mathrm{~s}^2, \sigma^* 1 \mathrm{~s}^2, \sigma 2 \mathrm{~s}^2, \sigma^* 2 \mathrm{~s}^2\left[\pi 2 \mathrm{p}_{\mathrm{x}}^2=\pi 2 \mathrm{p}_{\mathrm{y}}^2\right] \\ & \text { B.O. }=\frac{8-4}{2}=2 \\ & \mathrm{O}_2 \\ & \left(16 \mathrm{e}^{-}\right): \sigma 1 \mathrm{~s}^2, \sigma^* 1 \mathrm{~s}^2, \sigma 2 \mathrm{~s}^2, \sigma^* 2 \mathrm{~s}^2, \sigma 2 \mathrm{pz}^2 \\ & {\left[\pi 2 \mathrm{p}_{\mathrm{x}}^2=\pi 2 \mathrm{p}_{\mathrm{y}}^2\right]\left[\pi * 2 \mathrm{p}_{\mathrm{x}}^1=\pi * 2 \mathrm{p}_{\mathrm{y}}^1\right]} \\ & \text { B.O. }=\frac{10-6}{2}=2 \\ & \text { Be }{ }_2 \\ & \left(8 \mathrm{e}^{-}\right): \sigma 1 \mathrm{~s}^2, \sigma^* 1 \mathrm{~s}^2, \sigma 2 \mathrm{~s}^2, \sigma^* 2 \mathrm{~s}^2 \\ & \text { B.O. }=\frac{4-4}{2}=0 \\ & \mathrm{Li}_2 \\ & \left(6 \mathrm{e}^{-}\right): \sigma 1 \mathrm{~s}^2, \sigma^* 1 \mathrm{~s}^2, \sigma 2 \mathrm{~s}^2\end{aligned}$ $\begin{aligned} & \text { B.O. }=\frac{4-2}{2}=1 \\ & \mathrm{Ne}_2 \\ & \left(20 \mathrm{e}^{-}\right): \sigma 1 \mathrm{~s}^2, \sigma^* 1 \mathrm{~s}^2, \sigma 2 \mathrm{~s}^2, \sigma^* 2 \mathrm{~s}^2, \sigma 2 \mathrm{pz}^2 \\ & {\left[\pi 2 \mathrm{p}_{\mathrm{x}}^2=\pi 2 \mathrm{p}_{\mathrm{y}}^2\right]\left[\pi * 2 \mathrm{p}_{\mathrm{x}}^2=\pi^* 2 \mathrm{p}_{\mathrm{y}}^2\right] \sigma^* 2 \mathrm{p}_{\mathrm{z}}^2} \\ & \text { B.O. }=\frac{10-10}{2}=0 \\ & \mathrm{~N}_2 \\ & \left(14 \mathrm{e}^{-}\right): \sigma 1 \mathrm{~s}^2, \sigma^* 1 \mathrm{~s}^2, \sigma 2 \mathrm{~s}^2, \sigma^* 2 \mathrm{~s}^2\left[\pi 2 \mathrm{p}_{\mathrm{x}}^2=\pi 2 \mathrm{p}_{\mathrm{y}}^2\right] \sigma 2 \mathrm{p}_{\mathrm{z}}^2 \\ & \text { B.O. }=\frac{10-4}{2}=6 \\ & \mathrm{He}_2 \\ & \left(4 \mathrm{e}^{-}\right): \sigma 1 \mathrm{~s}^2, \sigma^* 1 \mathrm{~s}^2 \\ & \text { B.O. }=\frac{2-2}{2}=0\end{aligned}$

Asked in: JEE Main 2024 (08 Apr Shift 2)

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