Number of digits in $2^{10} \cdot 5^{8}$ is
Number of digits in $2^{10} \cdot 5^{8}$ is
- $8$
- $9$
- $10$
- $18$
Solution
$2^{10} \cdot 5^{8} = 2^{2} \cdot (2^{8} \cdot 5^{8}) = 4 \cdot 10^{8} = 400{,}000{,}000$, which has 9 digits.
Asked in: IMO
Practice more EXPONENTS AND POWERS questions on Aicharya