Number of different bonds present in \(\mathrm{P}_4 \mathrm{O}_{10}\) is
- \(8 \mathrm{P}-\mathrm{O}\) bonds and \(4 \mathrm{P}=\mathrm{O}\) bonds
- \(12 \mathrm{P}-\mathrm{O}\) bonds and \(3 \mathrm{P}=\mathrm{O}\) bonds
- \(12 \mathrm{P}-\mathrm{O}\) bonds and \(4 \mathrm{P}=\mathrm{O}\) bonds
- \(8 \mathrm{P}-\mathrm{O}\) bonds and \(3 \mathrm{P}=\mathrm{O}\) bonds
Asked in: AP EAMCET 2020 (18 Sep Shift 1)
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