Nucleus A is having mass number 220 and its binding energy per nucleon is 5 . 6   MeV . It splits in…

The total binding energy of nucleus $A$ is,

$E_A=220\times 5.6=1232 \mathrm{MeV}$

The total binding energy of $B$ and $C$ combined is,

$E_B+E_C=105\times 6.4+115\times 6.4=1408 \mathrm{MeV}$

Therefore, the energy released per fission is,

$Q=E_B+E_C-E_A=1408-1232=176 \mathrm{MeV}$