Nitrobenzene on reduction using zinc in alkaline medium results in $X$. The number of…

Nitrobenzene on reduction using zinc in alkaline medium results in $X$. The number of $\operatorname{sigma}(\sigma)$ and pi $(\pi)$ bonds in $X$ is
  1. $24 \sigma, 7 \pi$
  2. $24 \sigma, 6 \pi$
  3. $27 \sigma, 7 \pi$
  4. $27 \sigma, 6 \pi$

Solution

Nitrobenzene on reduction using zinc in alkaline medium gives hydrazobenzene.
Hydrazobenzene $(X)$ contains $27 \sigma$ and $6 \pi$ bonds.

Asked in: AP EAMCET 2011

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