Negation of the statement : $3+6>8$ and $2+3 < 6$ is
Negation of the statement : $3+6>8$ and $2+3 < 6$ is
$3+6 \leq 8 \text { or } 2+3 < 6$
$3+6 < 8 \text { or } 2+3 < 6$
$3+6 \leq 8 \text { or } 2+3 \geq 6$
$3+6>8 \text { or } 2+3 \geq 6$
Solution
Let $\mathrm{p}: 3+6>89$ and $\mathrm{q}: 2+3 < 6$
The logical form of given statement is $\mathrm{p} \wedge \mathrm{q}$.
$\therefore-(\mathrm{p} \wedge \mathrm{q}) \equiv \sim \mathrm{p} \vee \sim \text { q i.e. } 3+6 \leq 8 \text { or } 2+3 \geq 6$