Negation of $(p \wedge q) \rightarrow(\sim p \vee r)$ is
Negation of $(p \wedge q) \rightarrow(\sim p \vee r)$ is
- $\mathrm{p} \vee \mathrm{q} \vee(\sim \mathrm{r})$
- $\mathrm{p} \wedge \mathrm{q} \wedge \mathrm{r}$
- $\sim \mathrm{p} \wedge \mathrm{q} \wedge \mathrm{r}$
- $\mathrm{p} \wedge \mathrm{q} \wedge(\sim \mathrm{r})$
Solution
$\begin{aligned}
& \sim[(\mathrm{p} \wedge \mathrm{q}) \rightarrow(\sim \mathrm{p} \vee \mathrm{r})] \\
& \equiv \sim[\sim(\mathrm{p} \wedge \mathrm{q}) \vee(\sim \mathrm{p} \vee \mathrm{r})] \\
& \equiv(\mathrm{p} \wedge \mathrm{q}) \wedge \sim(\sim \mathrm{p} \vee \mathrm{r}) \\
& \equiv(\mathrm{p} \wedge \mathrm{q}) \wedge(\mathrm{p} \wedge \sim \mathrm{r}) \equiv \mathrm{p} \wedge \mathrm{q} \wedge(\sim \mathrm{r})
\end{aligned}$
Asked in: MHT CET 2021 (20 Sep Shift 2)
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