N 2 O 5 (   g ) → 2 NO 2 (   g ) + 1 2 O 2 (   g ) In the above first order reaction the initial concentration of N 2 O 5 is 2 . 40 × 10 - 2   mol   L - 1 at 318   K . The concentration of N 2 O 5 after 1 hour was 1 . 60 × 10 - 2   mol   L -…

Question

N 2 O 5 ( &#160; g ) &#8594; 2 NO 2 ( &#160; g ) + 1 2 O 2 ( &#160; g ) In the above first order reaction the initial concentration of N 2 O 5 is 2 . 40 &#215; 10 - 2 &#160; mol &#160; L - 1 at 318 &#160; K . The concentration of N 2 O 5 after 1 hour was 1 . 60 &#215; 10 - 2 &#160; mol &#160; L - 1 . The rate constant of the reaction at 318 &#160; K is &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#215; 10 - 3 &#160; min - 1 (Nearest integer): [ Given : log 3 = 0 . 477 , log 5 = 0 . 699 ]

Aicharya · Accepted Answer

K = 2 . 303 t log N 2 O 5 0 &#160; N 2 O 5 1 = 2 . 303 60 log 2 . 4 1 . 6 = 6 . 76 &#215; 10 - 3 &#160; min - 1 &#8776; 7 &#215; 10 - 3 &#160; min - 1

N 2 O 5 (   g ) → 2 NO 2 (   g ) + 1 2 O 2 (   g ) In the above first order reaction…

Solution

N 2 O 5 ( &#160; g ) &#8594; 2 NO 2 ( &#160; g ) + 1 2 O 2 ( &#160; g ) In the above first order reaction…

Solution

N 2 O 5 ( g ) → 2 NO 2 ( g ) + 1 2 O 2 ( g ) In the above first order reaction…