\(\lim _{n \rightarrow \infty} \frac{n !}{(n+1) !-n !}=\)

\(\lim _{n \rightarrow \infty} \frac{n !}{(n+1) !-n !}=\)
  1. 1
  2. -1
  3. 2
  4. 0

Solution

\(\begin{gathered} \operatorname{Lim}_{n \rightarrow \infty} \frac{n !}{(n+1) !-n !}=\operatorname{Lim}_{n \rightarrow \infty} \frac{1}{(n+1)-1} \\ =\operatorname{Lim}_{n \rightarrow \infty} \frac{1}{n}=0 \end{gathered}\)

Asked in: AP EAMCET 2020 (18 Sep Shift 1)

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