Multiply $(2x^{2} - 3y^{2})$ by $(x^{2} + y^{2})$.

Question

Aicharya · Accepted Answer

$2x^{2} \cdot x^{2} + 2x^{2}\cdot y^{2} - 3y^{2}\cdot x^{2} - 3y^{2}\cdot y^{2} = 2x^{4} + 2x^{2}y^{2} - 3x^{2}y^{2} - 3y^{4} = 2x^{4} - x^{2}y^{2} - 3y^{4}$.

Multiply $(2x^{2} - 3y^{2})$ by $(x^{2} + y^{2})$.

Solution