Moment of inertia of a square plate of side l about the axis passing through one of the corner and perpendicular to the plane of square plate is given by:

Question

Aicharya · Accepted Answer

Use parallel axis theorem to get the magnitude of the moment of inertia of a square plate of side $l$ about the axis passing through one of the corners and perpendicular to the plane of a square plate,

$I_{z} = I_{cm} + M {(\frac{l}{\sqrt{2}})}^{2}$

$\Rightarrow I_{z} = \frac{M l^{2}}{6} + \frac{M l^{2}}{2} = \frac{4 M l^{2}}{6} = \frac{2 M l^{2}}{3}$ .

Moment of inertia of a square plate of side l about the axis passing through one of the corner and…

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