Moment of inertia of a hollow cylinder of mass $\mathrm{M}$ and radius $\mathrm{r}$ about its own axis is
Moment of inertia of a hollow cylinder of mass $\mathrm{M}$ and radius $\mathrm{r}$ about its own axis is
- $\frac{2}{3} \mathrm{Mr}^{2}$
- $\frac{2}{5} \mathrm{Mr}^{2}$
- $\frac{1}{3} \mathrm{Mr}^{2}$
- $\mathrm{Mr}^{2}$
Solution
Moment of inertia of a hollow cylinder of mass $M$ and radius $r$ about its own axis is $M r^{2}$
Asked in: JEE Mains - Rotational Motion - Test 1
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