Moment of inertia of a body about a given axis is 1.5   k g   m 2 . Initially the body is at rest.…

Moment of inertia of a body about a given axis is 1.5 kg m2. Initially the body is at rest. In order to produce a rotational kinetic energy of 1200 J, the angular acceleration of 20 rad/s2 must be applied about the axis for a duration of:
  1. 3 s
  2. 2 s
  3. 2.5 s
  4. 5 s

Solution

We know that, 

Rotational kinetic energy, K=12Iω2 

12Iω2=1200
12×1.5×ω2=1200
ω=40 rad s-1

We also know that, ω=αt
t=4020=2 s

Asked in: JEE Main 2019 (09 Apr Shift 2)

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