Moment of inertia M . I . of four bodies, having same mass and radius, are reported as; I 1 = M . I . of…

Moment of inertia M.I. of four bodies, having same mass and radius, are reported as;

I1=M.I. of thin circular ring about its diameter,

I2=M.I. of circular disc about an axis perpendicular to disc and going through the centre,

I3=M.I. of solid cylinder about its axis and

I4=M.I. of solid sphere about its diameter.

Then:

  1. I1+I2=I3+52I4.
  2. I1+I3<I2+I4
  3. I1=I2=I3>I4
  4. I1=I2=I3<I4

Solution

Ring I1=MR22 about diameter

Disc I2=MR22

Solid cylinder I3=MR22

Solid sphere I4=25MR2

I1=I2=I3>I4

Asked in: JEE Main 2021 (24 Feb Shift 1)

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