Molten $\mathrm{CuCl}_2$ is electrolysed using platinum electrodes. The reaction occurring at anode is
- $2 \mathrm{Cl}^{-} \longrightarrow \mathrm{Cl}_2(g)+2 e^{-}$
- $\mathrm{Cl}_2(g)+2 e^{-} \longrightarrow 2 \mathrm{Cl}$
- $\mathrm{Cu}^{2+}+2 e^{-} \longrightarrow \mathrm{Cu}(s)$
- $\mathrm{Cu}(s) \longrightarrow \mathrm{Cu}^{2+}+2 e^{-}$
Solution
Asked in: JEE-TOPICTESTS-CHEMISTRY