Molecule AB has a bond length of 1.617   Å and a dipole moment of 0.38 D. The fractional charge on each atom(absolute magnitude) is: ( e 0 = 4.802 × 10 - 10   e s u )

Question

Molecule AB has a bond length of 1.617 &#160; &#8491; and a dipole moment of 0.38 D. The fractional charge on each atom(absolute magnitude) is: ( e 0 = 4.802 &#215; 10 - 10 &#160; e s u )

Aicharya · Accepted Answer

Assuming complete separation of charges (i.e. +e, -e on two ends)

μ = (4.802 \times 10^{- 10} e s u) \times (1.617 \times 10^{- 8} c m)

= 7.76 \times 10^{- 18} e s u . c m = 7.76 D

Fractional charge on dipole ends

= \frac{0.38}{7.76} ≅ 0.05

Molecule AB has a bond length of 1.617   Å and a dipole moment of 0.38 D. The fractional charge…

Solution

Molecule AB has a bond length of 1.617 &#160; &#8491; and a dipole moment of 0.38 D. The fractional charge…

Solution

Molecule AB has a bond length of 1.617 Å and a dipole moment of 0.38 D. The fractional charge…