Molecular bromine on reaction with three moles of molecular fluorine produces an inter halogen compound. The…
Molecular bromine on reaction with three moles of molecular fluorine produces an inter halogen compound. The total number of lone pairs at the central halogen atom is
3
2
1
0
Solution
Molecular bromine $\left(\mathrm{Br}_2\right)$ on reaction with 3 moles of molecular fluorine $\left(\mathrm{F}_2\right)$, it will produced 2 moles of $\mathrm{BrF}_3$.
$\mathrm{BrF}_3$ is interhalogen compound i.e. trifluorobromide.
$
\mathrm{Br}_2(g)+3 \mathrm{~F}_2(g) \longrightarrow \underset{\text { Trifluoro-bromide }}{2 \mathrm{BrF}_3(g)}
$
$\mathrm{BrF}_3=\frac{7 e^{-}+3 e^{-}}{2}=\frac{10}{2} e^{-}=5 e^{-}$i.e. $s p^3 d$ hybridisation.
$\mathrm{BrF}_3$ contain $3 \mathrm{Br}-\mathrm{F}^{-}$covalent bonds and 2 lone pairs.
$\mathrm{BrF}_3$ is $s p^3 d$ hybridised molecule having T-shape.
Hence, total number of lone pairs at central halogen atom is 2
