Molar conductivity of $0.04 \mathrm{M} \mathrm{BaCl}_2$ solution is $230 \Omega^{-1} \mathrm{~cm}^2…

Molar conductivity of $0.04 \mathrm{M} \mathrm{BaCl}_2$ solution is $230 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$ at $27^{\circ} \mathrm{C}$. what is its conductivity?
  1. $2.3 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$
  2. $9.2 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$
  3. $6.9 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$
  4. $4.6 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$

Solution

$\begin{aligned} & \Lambda_{\mathrm{m}}=\frac{\mathrm{k} \times 100}{\mathrm{M}} \\ & 230=\frac{\mathrm{k} \times 100}{0.04} \\ & \mathrm{k}=\frac{230 \times 0.04}{1000} \\ & =9.2 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\end{aligned}$

Asked in: MHT CET 2021 (22 Sep Shift 1)

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