Molar conductivity of $0.01 \mathrm{M} \mathrm{CH}_3 \mathrm{COOH}$ is $19.5 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$. Calculate its degree of dissociation if molar conductivity at zero concentration is $390 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$ ?

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Aicharya · Accepted Answer

$\begin{aligned} & \propto=\frac{\Lambda_m}{\Lambda_m^{\circ}}=\frac{19.5}{390} \ & =0.05\end{aligned}$

Molar conductivity of $0.01 \mathrm{M} \mathrm{CH}_3 \mathrm{COOH}$ is $19.5 \Omega^{-1} \mathrm{~cm}^2…

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