Molality of an aqueous solution of urea is \(4.44 \mathrm{~m}\). Mole fraction of urea in solution is \(x…
Molality of an aqueous solution of urea is \(4.44 \mathrm{~m}\). Mole fraction of urea in solution is \(x \times 10^{-3}\). Value of \(x\) is \(\qquad\) - (Integer answer)
Solution
Molality of urea is $4.44 \mathrm{~m}$, that means 4.44 moles of urea present in $1000 \mathrm{gm}$ of water.
$\therefore \mathrm{X}_{\text {ura }}=\frac{4.44}{4.44+\frac{1000}{18}}$
$=0.0740$
OR
$\begin{aligned} & 74 \times 10^{-3} \\ & X=74\end{aligned}$