mode, with a tuning fork is $0.1\text{ m}$. When this length is changed to $0.35\text{ m}$, the same tuning…

mode, with a tuning fork is $0.1\text{ m}$. When this length is changed to $0.35\text{ m}$, the same tuning fork resonates with the first overtone. Calculate the end correction.
  1. 0.012 m
  2. 0.025 m
  3. 0.05 m
  4. 0.024 m

Solution

Let $x$ be the end correction, then according to question, $\frac{v}{4(l_1 + x)} = \frac{3v}{4(l_2 + x)}$ $\Rightarrow x = 2.5\text{ cm} = 0.025\text{ m}$

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