Metallic silver has fcc structure. If radius of Ag atom is 144 pm . What is the edge length of unit cell?
Metallic silver has fcc structure. If radius of Ag atom is 144 pm . What is the edge length of unit cell?
$4.07 \times 10^{-8} \mathrm{~cm}$
$3.22 \times 10^{-8} \mathrm{~cm}$
$2.63 \times 10^{-8} \mathrm{~cm}$
$\quad .2 .23 \times 10^{-8} \mathrm{~cm}$
Solution
For fcc type of unit cell, $r=\frac{\sqrt{2}}{4} \mathrm{a}=0.3535 \mathrm{a}$
$\therefore \quad a=\frac{144 \mathrm{pm}}{0.3535}=407 \mathrm{pm}=4.07 \times 10^{-8} \mathrm{~cm}$