Mercurous chloride exists in the form of
- $\mathrm{Hg}^{+}$
- $\mathrm{Hg}_2^{2+}$
- $\mathrm{Hg}^{2+}$
- $\mathrm{Hg}_3{ }^{2+}$
Solution
\(\mathrm{Hg}+\mathrm{HgCl}_2 \rightarrow \mathrm{Hg}_2 \mathrm{Cl}_2\)
It can be prepared by metathesis reaction involving aqueous mercury nitrate using various chloride sources including NaCl or HCl
\(2 \mathrm{HCl}+\mathrm{Hg}_2\left(\mathrm{NO}_3\right)_2 \rightarrow \mathrm{Hg}_2 \mathrm{Cl}_2+2 \mathrm{HNO}_3\)
Now, \(\mathrm{HgCl}_2\) can be broken down into \(\mathrm{Hg}^2\) ions and \(\mathrm{Cl}^{-}\)ions. The chemical reaction is as given below:
\(\mathrm{Hg}_2 \mathrm{Cl}_2 \rightarrow \mathrm{Hg}_2{ }^{2+}+2 \mathrm{Cl}^{-}\)
Therefore, the answer to our question is option B.
Asked in: NEET 2020 (Phase 1)