Mean of $\dfrac{1}{2}, \dfrac{1}{3}, \dfrac{1}{6}$ is

Mean of $\dfrac{1}{2}, \dfrac{1}{3}, \dfrac{1}{6}$ is
  1. $\dfrac{1}{3}$
  2. $\dfrac{1}{2}$
  3. $\dfrac{1}{4}$
  4. $1$

Solution

Sum $= \dfrac{3+2+1}{6} = 1$. Mean $= \dfrac{1}{3}$.

Asked in: MH-SSC-9

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