Maximum number of electrons possible with spin quantum number $+\frac{1}{2}$ with principal quantum number…

Maximum number of electrons possible with spin quantum number $+\frac{1}{2}$ with principal quantum number $\mathrm{n}=4$ in an atom is
  1. $16$
  2. $9$
  3. $4$
  4. $25$

Solution

Maximum number of electrons $=2 n^2=2 \times 4 \times 4=32($ when $n=4)$ Half of the electrons have $\left(+\frac{1}{2}\right)$ spin, i.e., 16

Asked in: AP EAMCET 2022 (05 Jul Shift 2)

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