Maximum number of electrons possible with spin quantum number $+\frac{1}{2}$ with principal quantum number…
Maximum number of electrons possible with spin quantum number $+\frac{1}{2}$ with principal quantum number $\mathrm{n}=4$ in an atom is
- $16$
- $9$
- $4$
- $25$
Solution
Maximum number of electrons
$=2 n^2=2 \times 4 \times 4=32($ when $n=4)$
Half of the electrons have $\left(+\frac{1}{2}\right)$ spin, i.e., 16
Asked in: AP EAMCET 2022 (05 Jul Shift 2)
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