Maximum area of the rectangle inscribed in a circle of radius $10 \mathrm{cms}$ is

Question

Aicharya · Accepted Answer

Here ' $\mathrm{O}$ ' is centre of the circle as well as intersection point of diagonals of the square $A B C D$. Now from $\triangle \mathrm{ABC}$ $a^2+a^2=(20)^2 \Rightarrow 2 a^2=400$ $\Rightarrow a^2=200$

Maximum area of the rectangle inscribed in a circle of radius $10 \mathrm{cms}$ is

Solution