Match the reactions (in the given stoichiometry of the reactants) in List-I with one of their products given in List-II and choose the correct option.

List-I List-II

(P) $P_{2} O_{3} + 3 H_{2} O \to$ (1) $P (O) ({OCH}_{3}) {Cl}_{2}$

(Q) $P_{4} + 3 NaOH + 3 H_{2} O \to$ (2) $H_{3} {PO}_{3}$

(R) ${PCl}_{5} + {CH}_{3} COOH \to$ (3) ${PH}_{3}$

(S) $H_{3} {PO}_{2} + 2 H_{2} O + 4 {AgNO}_{3} \to$ (4) ${POCl}_{3}$

(5) $H_{3} {PO}_{4}$

Question

Match the reactions (in the given stoichiometry of the reactants) in List-I with one of their products given in List-II and choose the correct option.

	List-I		List-II
(P)	$P_{2} O_{3} + 3 H_{2} O \to$	(1)	$P (O) ({OCH}_{3}) {Cl}_{2}$
(Q)	$P_{4} + 3 NaOH + 3 H_{2} O \to$	(2)	$H_{3} {PO}_{3}$
(R)	${PCl}_{5} + {CH}_{3} COOH \to$	(3)	${PH}_{3}$
(S)	$H_{3} {PO}_{2} + 2 H_{2} O + 4 {AgNO}_{3} \to$	(4)	${POCl}_{3}$
		(5)	$H_{3} {PO}_{4}$

Aicharya · Accepted Answer

Phosphorus trioxide reacts with water to form phosphorous acid,
$P_{2} O_{3} + 3 H_{2} O \to 2 H_{3} {PO}_{3}$
When acetic acid is heated with phosphorus pentachloride, acetyl chloride is obtained. In this reaction, $- COOH$ group is converted to $- COCl$ group. The side products are phosphorus oxychloride and $HCl$ .
${PCl}_{5} + {CH}_{3} COOH \to {CH}_{3} COCl + {POCl}_{3} + HCl$
$P_{4}$ undergo disproportionation reaction with sodium hydroxide.
$P_{4} + 3 NaOH + 3 H_{2} O \overset{}{\to} {PH}_{3} + 3 {NaH}_{2} {PO}_{2}$
Due to the presence two $P - H$ bonds, $H_{3} {PO}_{2}$ acts as reducing agent. It reduces ${Ag}^{+}$ to $Ag$ .
$H_{3} {PO}_{2} + H_{2} O + {AgNO}_{3} \to H_{3} {PO}_{4} + {HNO}_{3} + Ag ↓$

Match the reactions (in the given stoichiometry of the reactants) in List-I with one of their products given…

Solution