Match the following List I with List II. $\begin{array}{|c|c|c|} \hline & \text { List I } & \text { List II…
Match the following List I with List II.
$\begin{array}{|c|c|c|}
\hline & \text { List I } & \text { List II } \\
\hline \text { (A) } & \text { Transverse wave (i) } & \begin{array}{l}
\text {Vibrations parallel to the } \\
\text {direction of propagation }
\end{array} \\
\hline \text { (B) } & \begin{array}{l}
\text {Longitudinal wave }
\end{array} & \begin{array}{l}
\text {Vibrations perpendicular to } \\
\text {the direction of propagation }
\end{array} \\
\hline \text { (C) } & \text { Beats } & \begin{array}{l}
\text {Superposition of waves } \\
\text {travelling in the opposite directions }
\end{array} \\
\hline \text { (D) } & \text { Stationary waves (iv) } & \begin{array}{l}
\text {Superposition of waves } \\
\text {travelling in same direction }
\end{array} \\
\hline
\end{array}$
The correct answer is
$\begin{array}{cccc} A & B & C & D \\ (ii) & (i) & (iii) & (iv) \end{array}$
$\begin{array}{cccc} A & B & C & D \\ (ii) & (i) & (iv) & (iii) \end{array}$
$\begin{array}{cccc} A & B & C & D \\ (iii) & (iv) & (i) & (ii) \end{array}$
$\begin{array}{cccc} A & B & C & D \\ (iv) & (i) & (ii) & (iii) \end{array}$
Solution
\(\mathbf{A} \rightarrow\) In transverse wave, vibrations are perpendicular to the direction of propagation. \(\mathbf{B} \rightarrow\) In longitudinal wave, the vibrations are parallel to the direction of propagation.
\(\mathbf{C} \rightarrow\) Beats are produced due to superposition of the waves travelling in same direction.
D \(\rightarrow\) Stationary waves are produced due to the superposition of waves, travelling in opposite direction.
Hence, the correct code is given by option (b).