
Match the following ( $f$ is number of degrees of freedom)

- A-III, B-IV, C-I, D-II
- A-II, B-I, C-III, D-IV
- A-IV, B-III, C-I, D-II
- A-II, B-III, C-IV, D-I
Solution
Mono atomic $(\mathrm{f}=3), \gamma=\left(1+\frac{2}{3}\right)=\frac{5}{3}$
Diatomic-rigid $(f=5), \gamma=\left(1+\frac{2}{5}\right)=\frac{7}{5}$
Diatomic-non-rigid $(\mathrm{f}=7), \gamma=\left(1+\frac{2}{7}\right)=\frac{9}{7}$
Polyatomic, $\gamma=\frac{4+\mathrm{f}}{3+\mathrm{f}}$
Asked in: AP EAMCET 2024 (21 May Shift 2)