Match List- I with List- II . List- I List- II (Molecule) (Bond order) (a) Ne 2 (i) 1 (b) N 2 (ii) 2 (c) F 2…

Match List-I with List-II.

List-I List-II
(Molecule) (Bond order)
(a) Ne2 (i) 1
(b) N2 (ii) 2
(c) F2 (iii) 0
(d) O2 (iv) 3

Choose the correct answer from the options given below:

  1. a→ii, b→i, c→iv, d→iii
  2. a→iii, b→iv, c→i, d→ii
  3. a→i, b→ii, c→iii, d→iv
  4. a→iv, b→iii, c→ii, d→i

Solution

Bond order = 12​ (number of electrons in bonding MO -number of electrons in anti-bonding MO)

(a) Ne2= Total eΘ=20

B.O. =10-102=0

(b) N2= Total e⊝=14

B.O. =10-42=3

(c) F2= Total e⊝=18

B.O. =10-82=1

(d) O2= Total e⊝=16

B.O. =10-62=2

Asked in: JEE Main 2021 (26 Feb Shift 2)

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