Match List I with List II. Choose the correct answer from the options given below:
Match List I with List II.
Choose the correct answer from the options given below:
- A-III, B-IV, C-I, D-II
- A-II, B-III, C-I, D-IV
- A-III, B-IV, C-II, D-I
- A-II, B-IV, C-I, D-III
Solution
$\therefore 4 \mathrm{OH}^{-} \rightarrow 2 \mathrm{H}_2 \mathrm{O}+\mathrm{O}_2+4 \mathrm{e}^{-}$
for 2 mole of $\mathrm{H}_2 \mathrm{O}=4 \mathrm{~F}$ charge is required for 1 mole of $\mathrm{H}_2 \mathrm{O}=\frac{4 F}{2}=2 \mathrm{~F}$ required
$\stackrel{+7}{\mathrm{MnO}_4^{-}} \rightarrow \stackrel{+2}{\mathrm{Mn}}{ }^{2+}$
for 1 mole $\mathrm{MnO}_4^{-} 5 \mathrm{~F}$ charge is required
$\mathrm{Ca}^{2+} \xrightarrow{+2 \mathrm{e}^{-}} \mathrm{Ca}$
For 1 mole $\mathrm{Ca}^{2+}$ ion required $=2 \mathrm{~F}$
1.5 mole $\mathrm{Ca}^{2+}$ ion required $=\frac{2}{1} \times 1.5=3 \mathrm{~F}$
$\stackrel{+2}{\mathrm{FeO}} \rightarrow \stackrel{+3}{\mathrm{Fe}} \mathrm{O}_2 \mathrm{O}_3$
for 1 mole $\mathrm{FeO}, 1 \mathrm{~F}$ charge is required.
Asked in: NEET 2024
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