Match List - I with List - II. $\begin{array}{llll} & \text{List - I} & & \text{List - II} \\ A. &…
$\begin{array}{llll} & \text{List - I} & & \text{List - II} \\ A. & \text{Coefficient of viscosity} & I. & [M L^{-1} T^{-1}] \\ B. & \text{Surface tension} & II. & [M L^{0} T^{-2}] \\ C. & \text{Pressure} & III. & [M L^{-1} T^{-2}] \\ D. & \text{Surface energy} & IV. & [M L^{2} T^{-2}] \end{array}$
Choose the correct answer from the options given below :
- A-IV, B-III, C-I, D-II
- A-IV, B-I, C-II, D-III
- A-I, B-II, C-IV, D-III
- A-I, B-III, C-II, D-IV
Solution
$\eta = \frac{F \cdot dr}{A \cdot dv} = \frac{[MLT^{-2}][L]}{[L^2][LT^{-1}]} = [ML^{-1}T^{-1}]$ → IV
(B) Surface tension:
$S = \frac{F}{L} = \frac{[MLT^{-2}]}{[L]} = [MT^{-2}] = [ML^0T^{-2}]$ → III
(C) Pressure:
$P = \frac{F}{A} = \frac{[MLT^{-2}]}{[L^2]} = [ML^{-1}T^{-2}]$ → I
(D) Surface energy:
$E = S \times A = [MT^{-2}][L^2] = [ML^2T^{-2}]$ → II
Hence, A-IV, B-III, C-I, D-II.
Asked in: JEE Main 2026 (28 Jan Shift 2)