Match List-I with List-II. \(\begin{array}{|l|l|l|l|} \hline & \text{List - I} & & \text{List - II} \\…
\(\begin{array}{|l|l|l|l|} \hline & \text{List - I} & & \text{List - II} \\ \hline \text { (A) } & \text { Isobaric } & \text { (I) } & \Delta Q=\Delta W \\ \hline \text { (B) } & \text { Isochoric } & \text { (II) } & \Delta Q=\Delta U \\ \hline \text { (C) } & \text { Adiabatic } & \text { (III) } & \Delta Q=\text { zero } \\ \hline \text { (D) } & \text { Isothermal } & \text { (IV) } & \Delta Q=\Delta U+P \Delta V \\ \hline \end{array}\)
$\Delta \mathrm{Q}=$ Heat supplied
$\Delta \mathrm{W}=$ Work done by the system
$\Delta \mathrm{U}=$ Change in internal energy
$\mathrm{P}=$ Pressure of the system
$\Delta \mathrm{V}=$ Change in volume of the system
Choose the correct answer from the options given below:
- (A)-(IV), (B)-(III), (C)-(II), (D)-(I)
- (A)-(IV), (B)-(I), (C)-(III), (D)-(II)
- (A)-(IV), (B)-(II), (C)-(III), (D)-(I)
- (A)-(II), (B)-(IV), (C)-(III), (D)-(I)
Solution
$\Delta \mathrm{Q}=\Delta \mathrm{U}+\mathrm{P} \Delta \mathrm{~V}$
(B) Isochoric $(\mathrm{V}=\mathrm{C})$
$\Delta \mathrm{Q}=\Delta \mathrm{U}$
(C) Adiabatic $(\Delta \mathrm{Q}=0)$
$\Delta \mathrm{Q}=0$
(D) Isothermal $(\Delta \mathrm{U}=0)$
$\Delta \mathrm{Q}=\Delta \mathrm{W}$
Asked in: JEE Main 2025 (04 Apr Shift 2)