Match List I with List II : $\begin{array}{|l|l|r|l|}\hline & \text{List-I} & & \text{List-II} \\\hline A. &…

Match List I with List II : $\begin{array}{|l|l|r|l|}\hline & \text{List-I} & & \text{List-II} \\\hline A. & \text{Lipase} & I. & \text{Peptide bond} \\\hline B. & \text{Nuclease} & II. & \text{Ester bond} \\\hline C. & \text{Protease} & III. & \text{Glycosidic bond} \\\hline D. & \text{Amylase} & IV. & \text{Phosphodiester bond} \\\hline\end{array}$ Choose the correct answer from the options given below :
  1. A-III, B-II, C-I, D-IV
  2. A-II, B-IV, C-I, D-III
  3. A-IV, B-I, C-III, D-II
  4. A-IV, B-II, C-III, D-I

Solution

The correct answer is option (2) as $\begin{array}{|l|l|l|l|}\hline A. & \text{Lipase} & - & \text{Digests ester bond found in lipids.} \\ \hline B. & \text{Nuclease} & - & \text{Helps in digestion of phosphodiester bonds found in nucleic acids.} \\ \hline C. & \text{Protease} & - & \text{Helps in digestion of peptide bond found in proteins.} \\ \hline D. & \text{Amylase} & - & \begin{array}{l} \text{Digests/breaks the glycosidic bonds found in carbohydrates i.e., digest} \\ \text{starch into smaller molecules, ultimately yielding maltose, which in turn is} \\ \text{cleaved into two glucose molecules by maltase.} \end{array} \\ \hline\end{array}$

Asked in: NEET 2024

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