Match List I with List II. \begin{tabular}{|l|l|l|l|} \hline & \multicolumn{1}{|c|}{List I (Spectral Lines…

Match List I with List II. \begin{tabular}{|l|l|l|l|} \hline & \multicolumn{1}{|c|}{List I (Spectral Lines of Hydrogen for transitions from)} & & \multicolumn{1}{|c|}{List II (Wavelengths (nm))} \\\hline A. & $n_{2}=3$ to $m_{1}=2$ & I. & 410.2 \\\hline B. & $n_{2}=4$ to $m_{1}=2$ & II. & 434.1 \\\hline C. & $n_{2}=5$ to $n_{1}=2$ & III. & 656.3 \\\hline D. & $n_{2}=6$ to $n_{1}=2$ & IV. & 486.1 \\\hline \end{tabular} Choose the correct answer from the options given below:
  1. A-III, B-IV, C-III, D-I
  2. A-IV, B-III, C-I, D-II
  3. A-I, B-II, C-III, D-IV
  4. A-II, B-I, C-IV, D-III

Solution

Energy difference $\Delta E=\frac{h c}{\lambda}$ $\begin{aligned} & \therefore \lambda \propto \frac{1}{\Delta E} \\ & (\Delta E)_{6-2}\gt(\Delta E)_{5-2}\gt(\Delta E)_{4-2}\gt(\Delta E)_{3-2} \\ & \lambda_{6-2} \lt \lambda_{5-2} \lt \lambda_{4-2} \lt \lambda_{3-2} \end{aligned}$ A-III, B-IV, C-II, D-I

Asked in: NEET 2024

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