Match List - I with List - II. $\begin{array}{lll} \begin{array}{l} \text { List - I } \\ \text { (Complex…

Match List - I with List - II. $\begin{array}{lll} \begin{array}{l} \text { List - I } \\ \text { (Complex ion) } \end{array} & \begin{array}{l} \text { List - II } \\ \text { (Spin only magnetic moment in B.M.) } \end{array} \\ \text { (A) }[\mathrm{Cr}(\mathrm{NH}_{3})_{6}]^{3+} & \text { (I) } 4.90 \\ \text { (B) }[\mathrm{NiCl}_{4}]^{2-} & \text { (II) } 3.87 \\ \text { (C) }[\mathrm{CoF}_{6}]^{3-} & \text { (III) } 0.0 \\ \text { (D) }[\mathrm{Ni}(\mathrm{CN})_{4}]^{2-} & \text { (IV) } 2.83 \end{array}$ Choose the correct answer from the options given below:
  1. (A)-(II), (B)-(III), (C)-(I), (D)-(IV)
  2. (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
  3. (A)-(I), (B)-(IV), (C)-(II), (D)-(III)
  4. (A)-(IV), (B)-(III), (C)-(I), (D)-(II)

Solution

$\begin{aligned} & \text { (A) }\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_6\right]^{3+} \\ & \mathrm{Cr}^{3+}: 3 \mathrm{~d}^3 \\ & \mathrm{n}=3 \text { (unpaired electrons) } \\ & \mu \simeq 3.87 \text { B.M. (II) } \\ & \end{aligned}$ $\begin{aligned} & \text { (B) }\left[\mathrm{NiCl}_4\right]^{2-} \\ & \mathrm{Ni}^{2+}: 3 \mathrm{~d}^8 \\ & \mathrm{n}=2 \\ & \mu \simeq 2.83 \text { B.M. (IV) } \\ & \end{aligned}$ $\begin{aligned} & \text { (C) }\left[\mathrm{CoF}_6\right]^{3-} \\ & \mathrm{Co}^{3+}: 3 \mathrm{~d}^6 \\ & \mathrm{n}=4 \\ & \mu \simeq 4.90 \text { B.M. (I) }\end{aligned}$ $\begin{aligned} & \text { (D) }\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-} \\ & \mathrm{Ni}^{2+}: 3 \mathrm{~d}^8 \\ & \mathrm{n}=0 \\ & \mu=0 \text { B.M. (III) } \\ & \end{aligned}$
SECTION -B

Asked in: JEE Main 2024 (08 Apr Shift 2)

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