Match List I (species) and List II (bond orders) and select the correct answer: $\begin{array}{ll}\text {…

Match List I (species) and List II (bond orders) and select the correct answer:
$\begin{array}{ll}\text { List-I } & \text { List-II } \\ \text { A. } \mathrm{N}_{2} & 1.~1 .0 \\ \text { B. } \mathrm{O}_{2} & 2.~2 .0 \\ \text { C. } \mathrm{F}_{2} & 3.~2 .5 \\ \text { D. } O_{2}^{+} & \text {4. } 3.0\end{array}$
  1. $\mathrm{A} ightarrow 4, \mathrm{~B} ightarrow 2, \mathrm{C} ightarrow 1, \mathrm{D} ightarrow 3$
  2. $\mathrm{A} ightarrow 1, \mathrm{~B} ightarrow 3, \mathrm{C} ightarrow 4, \mathrm{D} ightarrow 2$
  3. $\mathrm{A} ightarrow 1, \mathrm{~B} ightarrow 2, \mathrm{C} ightarrow 4, \mathrm{D} ightarrow 3$
  4. $\mathrm{A} ightarrow 4, \mathrm{~B} ightarrow 3, \mathrm{C} ightarrow 1, \mathrm{D} ightarrow 2$

Solution

$N_{2} ightarrow \sigma(2 s)^{2} \sigma(2 s)^{*2} \pi(2 P x)^{2} \pi(2 p y)^{2} \sigma(2 p z)^{2}$ Bond order $=\frac{1}{2}(8-2)=3$
$O_{2} ightarrow$ bond order $=\frac{1}{2}(8-4)=2$
$F_{2} ightarrow$ bond order $=\frac{1}{2}(8-6)=1$
$O_{2}^{+} ightarrow$ bond order $=\frac{1}{2}(8-3)=2.5$ ^

Asked in: JEE-TOPICTESTS-CHEMISTRY

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