Match each set of hybrid orbitals from LIST-I with complex (es) given in LIST-II. LIST -I LIST -II A) d s p…

1. - $\mathrm{A} \rightarrow \mathrm{U}$ - $B \rightarrow T, S$ - $C \rightarrow P, Q$ - $\mathrm{D} \rightarrow \mathrm{R}$
2. - $A \rightarrow P$ - B $\rightarrow$ S - $\mathrm{C} \rightarrow \mathrm{Q}, \mathrm{R}$ - $\mathrm{D} \rightarrow \mathrm{T}, \mathrm{U}$
3. - $A \rightarrow T$ - $B \rightarrow P, U$ - $\mathrm{C} \rightarrow \mathrm{S}$ - $\mathrm{D} \rightarrow \mathrm{Q}, \mathrm{R}$
4. - $\mathrm{A} \rightarrow \mathrm{S}$ - $B \rightarrow T, R$ - $\mathrm{C} \rightarrow \mathrm{P}, \mathrm{U}$ - $\mathrm{D} \rightarrow \mathrm{Q}$

Solution

$\left(P\right)$ ${\left[Fe{F}_6\right]}^{4-}$

$\left(Q\right)$ $\left[Ti{\left(H_{2}O\right)}_{3}C{l}_3\right]$

$\left(R\right)$ ${\left[Cr{\left(N{H}_3\right)}_6\right]}^{3+}$

$\left(S\right)$ ${\left[FeC{l}_4\right]}^{2-}$

$\left(T\right)$ $\left[Ni{\left(CO\right)}_4\right]$
$Ni :3d^{8}e{S}^2$

Back pairing of elements due to pressure of strong field ligand

$\left(U\right)$ ${\left[Ni{\left(CN\right)}_4\right]}^{2-}$
$N{I}^{2+} :3d^8$

Asked in: JEE Advanced 2018 (Paper 2)

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