
Match Column-I with Column-II and select the correct answer by the given codes.

- $\mathrm{A}-(\mathrm{s}), \mathrm{B}-(\mathrm{q}), \mathrm{C}-(\mathrm{r}), \mathrm{D}-(\mathrm{p})$
- $A-(p), B-(s), C-(q), D-(r)$
- $\mathrm{A}-(\mathrm{s}), \mathrm{B}-(\mathrm{p}), \mathrm{C}-(\mathrm{r}), \mathrm{D}-(\mathrm{q})$
- $\mathrm{A}-(\mathrm{s}), \mathrm{B}-(\mathrm{p}), \mathrm{C}-(\mathrm{q}), \mathrm{D}-(\mathrm{r})$
Solution
Fluorine (F) $1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{3} ightarrow$ High electronegativity in nature due to small size and $-1$ oxidation state.
Rubidium (Rb) $ightarrow$ Most electropositive element due to large atomic size.
Lithium (Li) $\quad ightarrow$ Strongest reducing agent due to small size and positive oxidation state $(+1)$
Asked in: JEE-TOPICTESTS-CHEMISTRY
Practice more CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES questions on Aicharya